x^4-1x^2+80=0

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Solution for x^4-1x^2+80=0 equation:


Simplifying
x4 + -1x2 + 80 = 0

Reorder the terms:
80 + -1x2 + x4 = 0

Solving
80 + -1x2 + x4 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-80' to each side of the equation.
80 + -1x2 + -80 + x4 = 0 + -80

Reorder the terms:
80 + -80 + -1x2 + x4 = 0 + -80

Combine like terms: 80 + -80 = 0
0 + -1x2 + x4 = 0 + -80
-1x2 + x4 = 0 + -80

Combine like terms: 0 + -80 = -80
-1x2 + x4 = -80

The x term is -1x2.  Take half its coefficient (-0.5).
Square it (0.25) and add it to both sides.

Add '0.25' to each side of the equation.
-1x2 + 0.25 + x4 = -80 + 0.25

Reorder the terms:
0.25 + -1x2 + x4 = -80 + 0.25

Combine like terms: -80 + 0.25 = -79.75
0.25 + -1x2 + x4 = -79.75

Factor a perfect square on the left side:
(x2 + -0.5)(x2 + -0.5) = -79.75

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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